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What number must be added to each of 45, 13, 33 and 9 such that the resultant numbers are in proportion?
- A4
- B3
- C13
- D12
Answer not set
Discussion 1
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CCommunity
Let the number to be added be ‘m’, then according to the question,
$(\frac{{45 + m}}{{13 + m}} = \frac{{33 + m}}{{9 + m}})$
⇒ 405 + 9m + 45m + m2 = 429 + 33m + 13m + m2
⇒ 54m – 46m = 429 – 405
⇒ 8m = 24
⇒ m = 3
Since, the required answer is 3.
$(\frac{{45 + m}}{{13 + m}} = \frac{{33 + m}}{{9 + m}})$
⇒ 405 + 9m + 45m + m2 = 429 + 33m + 13m + m2
⇒ 54m – 46m = 429 – 405
⇒ 8m = 24
⇒ m = 3
Since, the required answer is 3.