[13 + 23 + 33 + ……. + 93 + 103] is equal to

Using the standard identity that the sum of first n cubes is $({\left[ {\frac{{n\left( {n + 1} \right)}}{2}} \right]^2})$, we have

13 + 23 + 33 + ……. + 93 + 103 = $({\left[ {\frac{{10\left( {10 + 1} \right)}}{2}} \right]^2} = {55^2} = 3025)$