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Greatest number of 4 digits which is divisible by each one of 12, 18, 21 and 28 is
- A9821
- B9828
- C9892
- DCannot be determined
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CCommunity
In this case we will evaluate the LCM of 12, 18, 21, 28 which is 252
The required number must be divisible by 252. However it should be the greatest four digit number.
We know that the greatest 4 digit number is 9999.
On dividing 9999 by 252, the remainder is 171.
∴ The number should be (9999 - 171) or 9828.
The required number must be divisible by 252. However it should be the greatest four digit number.
We know that the greatest 4 digit number is 9999.
On dividing 9999 by 252, the remainder is 171.
∴ The number should be (9999 - 171) or 9828.