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A train does a journey without stoppage in 8 hours, if it had travelled 5 km/h faster, it would have done the journey in 6 hours 40 minutes. Find its original speed.
- A25 km/h
- B40 km/h
- C45 km/h
- D36.5 km/h
Answer not set
Discussion 1
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CCommunity
Let original speed = S km/h
Here, distance to be covered is constant
⇒ S × 8 = (S + 5)(20⁄3)
⇒ 8S - 20⁄3S = 100⁄3
⇒ S = 100⁄4
∴ S = 25 km/h
Here, distance to be covered is constant
⇒ S × 8 = (S + 5)(20⁄3)
⇒ 8S - 20⁄3S = 100⁄3
⇒ S = 100⁄4
∴ S = 25 km/h