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If x + y = 4, then what is the value of \(\frac{2}{{x - 2}} + \frac{2}{{y - 2}}?\) (x, y ≥ 0)
- A-1
- B0
- C4
- D16
Answer not set
Discussion 1
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0
CCommunity
Possible cases are: 1. x = 4 and y = 0 or vice versa
2. x = 3 and y = 1 or vice versa (answer would come same in all the cases)
Let us assume x = 3 and y = 1 which satisfies the condition x + y = 4
⇒ 2/(x - 2) + 2/(y - 2)
⇒ 2/(3 - 2) + 2/(1 - 2) = 0
∴ 2/(x - 2) + 2/(y - 2) = 0
[Note: We cannot take x = y = 2, because division by 0 is not defined]
2. x = 3 and y = 1 or vice versa (answer would come same in all the cases)
Let us assume x = 3 and y = 1 which satisfies the condition x + y = 4
⇒ 2/(x - 2) + 2/(y - 2)
⇒ 2/(3 - 2) + 2/(1 - 2) = 0
∴ 2/(x - 2) + 2/(y - 2) = 0
[Note: We cannot take x = y = 2, because division by 0 is not defined]