10 liters are removed from a cask full of wine containing 60 liters and is then filled with water. 10 liters of mixture is again withdrawn… — Answer & Discussion

10 liters are removed from a cask full of wine containing 60 liters and is then filled with water. 10 liters of mixture is again withdrawn from the container. What quantity of wine is now left in the cask?

A$41\frac{2}{3}$
B$27\frac{3}{6}$
C40
D35

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Discussion 1

CCommunity06 Jun 2019

Initial amount of wine = 60 liters.

After replacing 10 liters of wine with water

⇒ There is 50 liters of wine and 10 liters of water.

⇒ Wine to water ratio = 5: 1

10 liters of this mixture is removed and replaced by water.

⇒ Amount of wine removed from the mixture = (5/6) × 10 = 25/3 liters.

Amount of water removed = (1/6) × 10 = 5/3 liters.

Final amount of wine in the mixture = 50 – 25/3 = 125/3 = $(41\frac{2}{3})$ liters.