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The voltage phasor of a circuit is 10∠15° V and current phasor is 2∠-45° A. The reactive power in the circuit will be
- A17.32 VAR
- B10√2 VAR
- C8.66 VAR
- DNone of these
Answer not set
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CCommunity
V = 10∠15° V
I = 2∠-45° A
Phase difference (?) = 15 - (-45) = 60°
Reactive power = VI sin ? = 10 × 2 × sin 60° = 17.32 VAR
I = 2∠-45° A
Phase difference (?) = 15 - (-45) = 60°
Reactive power = VI sin ? = 10 × 2 × sin 60° = 17.32 VAR