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A dealer sells two machines at Rs. 12000 each. On one it gains 32% and on the other it loses 32%. What is its profit/loss percentage in the whole transaction?
- ANo gain and no loss
- B1% loss
- C18% profit
- D10.24% loss
Answer not set
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Let the cost price of one article be Rs. y and other be Rs. z
From the given problem statement, 32% gain can be given as
⇒ y × (1 + 32/100) = 12000
⇒ y = 12000/1.32
⇒ y = Rs. 9090.9
32% loss can be written as
⇒ z × (1 – 32/100) = 12000
⇒ z = 12000/.68
⇒ z = 17647.05
⇒ Total cost price = 9090.9 + 17646.05 = Rs. 26736.95
⇒ Total selling price = 12000 + 12000 = Rs. 24000
⇒ Loss = 26736.95 – 24000 = Rs. 2736.95
⇒ Loss percent = loss × 100/CP = 2736.95 × 100/26736.95
⇒ Loss percent = 10.24%
∴ Loss percent is 10.24%
From the given problem statement, 32% gain can be given as
⇒ y × (1 + 32/100) = 12000
⇒ y = 12000/1.32
⇒ y = Rs. 9090.9
32% loss can be written as
⇒ z × (1 – 32/100) = 12000
⇒ z = 12000/.68
⇒ z = 17647.05
⇒ Total cost price = 9090.9 + 17646.05 = Rs. 26736.95
⇒ Total selling price = 12000 + 12000 = Rs. 24000
⇒ Loss = 26736.95 – 24000 = Rs. 2736.95
⇒ Loss percent = loss × 100/CP = 2736.95 × 100/26736.95
⇒ Loss percent = 10.24%
∴ Loss percent is 10.24%