CCommunity
Let the first even number A be = x + 2
Then E = (x + 10)
Average of A and E = 46
Largest number = $(\frac{{{\rm{x\;}} + {\rm{\;}}2{\rm{\;}} + {\rm{\;x\;}} + {\rm{\;}}10}}{2}{\rm{\;}} = {\rm{\;}}46)$
⇒ 2x + 12 = 92
⇒ x = 40
∴ E = x + 10 = 40 + 10 = 50.
Hence, 50 is the largest number.