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If P got 20% marks less than Q, then the marks of Q is how much percent more than P?
- A20
- B10
- C25
- D15
Answer not set
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CCommunity
Let the marks obtained by Q be x
Marks obtained by P = x - 20/100 × x = 0.8x
Percentage marks Q has more than P = (Difference in marks)/(Marks obtained by P) × 100 = 25%
Percentage marks Q has more than P = (x - 0.8x)/0.8x × 100 = 25%
Marks obtained by P = x - 20/100 × x = 0.8x
Percentage marks Q has more than P = (Difference in marks)/(Marks obtained by P) × 100 = 25%
Percentage marks Q has more than P = (x - 0.8x)/0.8x × 100 = 25%