Find the maximum number of odd days in 49 years

Counting odd days and calculating day of any particular date$

1 ordinary year = 365 days = (52 weeks + 1 day).$

Hence, number of odd days in 1 ordinary year = 1$

1 leap year = 366 days = (52 weeks + 2 days).$

Hence number of odd days in 1 leap year = 2.$

49 years = (37 ordinary years + 12 leap years).for maximum odd days$

= (37 × 1 + 12 × 2) odd days, $

= 61 odd days,$

= 8 weeks + 5 days $= 5 odd days$