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The mean proportional between (3 + √2) and (12 - √32) is
- A√7
- B2√7
- C6
- D\(\frac{{15 - 3\sqrt 2 }}{2}\)
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Discussion 1
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CCommunity
To find the mean proportion between any two numbers, any variable say x is to be assumed as mean proportion, this makes the equation as,
(3+ √2):x :: x:(12 - √32)
⇒ (3 + √2)/x = x/(12 - √32)
⇒ X2 = (3 + √2) (12 - √32)
⇒ X2 = 4(3 + √2) (3 - √2)
⇒ X2 = 4 x 7
⇒ X2 = 28
⇒ X = 2$(\sqrt 7)$
(3+ √2):x :: x:(12 - √32)
⇒ (3 + √2)/x = x/(12 - √32)
⇒ X2 = (3 + √2) (12 - √32)
⇒ X2 = 4(3 + √2) (3 - √2)
⇒ X2 = 4 x 7
⇒ X2 = 28
⇒ X = 2$(\sqrt 7)$