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A 50 litre mixture of water and alcohol contains 10% alcohol. How much more alcohol must be added to make the strength of alcohol 40% in the new mixture?
- A25
- B30
- C20
- D23
Answer not set
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CCommunity
Alcohol quantity in 50 liter mixture = 50 × 10/100 = 5 Litre
Let the quantity of alcohol which added = x liters
According to question
⇒ (5 + x)/(50 + x) = 40%
⇒ (5 + x)/(50 + x) = 40/100
⇒ x = 25 liter
Let the quantity of alcohol which added = x liters
According to question
⇒ (5 + x)/(50 + x) = 40%
⇒ (5 + x)/(50 + x) = 40/100
⇒ x = 25 liter