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A chord AB of a circle C1 of radius (√5 + 2) cm, touches a circle C2 which is concentric to O. If the radius of C2 is (√5 - 2) cm then length of AB is –
- A\(4\sqrt {20}\) cm
- B\(4\sqrt[4]{{20}}\) cm
- C\(2\sqrt[8]{{20}}\) cm
- D\(4\sqrt[8]{{20}}\) cm
Answer not set