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Average of the marks of 132 students of a college is 40. If the average of the marks of the passed students is 42 and the average of the ma…

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Average of the marks of 132 students of a college is 40. If the average of the marks of the passed students is 42 and the average of the marks of the failed students is 20, then what will be the respective ratio of the total marks of passed students and the total marks of failed students?
  • A21 ∶ 1
  • B23 ∶ 2
  • C19 ∶ 11
  • D9 ∶ 2
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Average of marks of 132 students = Sum of marks of 132 students/132

⇒ 40 = Sum of marks of 132 students/132

⇒ Sum of marks of 132 students = 5280

Let number of passed student be x

Number of failed student = 132 – x

Now,

Average of marks of passed student = sum of marks of passed students/x

⇒ 42 = sum of marks of passed students /x

⇒ sum of marks of passed students = 42x

Now,

Average of marks of failed student = sum of marks of failed students/(132 – x)

⇒ 20 = sum of marks of failed students /(132 – x)

⇒ sum of marks of failed students = 20(132 – x) = 2640 – 20x

Now,

Total sum = 42x + 2640 – 20x

⇒ 5280 = 22x + 2640

⇒ 22x = 2640

⇒ x = 120

Total marks of passed student = 42x = 42 × 120 = 5040

⇒ Total marks of failed student = 2640 – 20x = 2640 – 20(120) = 240

∴ Required ratio = 5040 ? 240 = 21 ? 1