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Find the least number which should be added to 1456 so that it is divisible by 6, 5 and 4 without leaving a remainder.
- A6
- B61
- C44
- D16
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CCommunity
LCM (6, 5, 4) = 60
So, here we require the least number greater than 1456 which is divisible by 60.
1456 = 60 × 24 + 16
∴ To make the number divisible, we will have to add (60 - 16) = 44
So, here we require the least number greater than 1456 which is divisible by 60.
1456 = 60 × 24 + 16
∴ To make the number divisible, we will have to add (60 - 16) = 44