CCommunity
Let the quantity of new mixture is ‘a’ litres
Acid in the mixture = 20% of 80 litre = 16 litres
Water in the mixture = 80 – 16 = 64 litres = 80% of the mixture
In new mixture water is only 40% and acid is 60%
Water in new mixture = 40% of a litres = 64 litres
⇒ 2/5 × a = 64 litres
⇒ a = 160 litres
Acid in new mixture = 160 – 64 = 96 litres = 60% of the new mixture
∴ Acid that should be added = 96 – 16 = 80 litres