Three toys are in a shape of cylinder, hemisphere and cone. The three toys have same base. Height of each toy is 2√2 cm. What is the ratio…

Base is same hence radius will also be same, let, radius be ‘r’ and h = 2√2 cm

Since for hemisphere r = h,

⇒ base radius = height = 2√2 cm

Total surface area of cylinder = 2πrh + 2πr2

⇒ Total surface area of cylinder = 2πr(h + r)

⇒ Total surface area of cylinder = 4πr2 [r = h]

⇒ Total surface area of hemisphere = 3πr2

⇒ Total surface area of cone = πrl + πr2

⇒ Total surface area of cone = πr[√(r2 + h2)] + πr2

⇒ Total surface area of cone = √2πr2 + πr2

⇒ Total surface area of cone = πr2(√2 + 1)

∴ Ratio of the total surface areas of cylinder, hemisphere and cone = 4 ? 3 ? [(√2) + 1]