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An error of 3% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is
- A3%
- B3.03%
- C6%
- D6.09%
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⇒ Area of Square = Side2
⇒ Let the side of Square be x
⇒ Area = x2
If the error of 3% in excess is made while measuring the length of the side of the square
⇒ Length Measured due to error = x + 3% of x = 1.03x
∴ Area of Square due to error= `1.03x × 1.03x = 1.0609x2
⇒ Error in Area = 1.0609x2-x2 = 0.0609x2
⇒ % Error in Area = (0.0609x2/x2) × 100 = 6.09%
⇒ Let the side of Square be x
⇒ Area = x2
If the error of 3% in excess is made while measuring the length of the side of the square
⇒ Length Measured due to error = x + 3% of x = 1.03x
∴ Area of Square due to error= `1.03x × 1.03x = 1.0609x2
⇒ Error in Area = 1.0609x2-x2 = 0.0609x2
⇒ % Error in Area = (0.0609x2/x2) × 100 = 6.09%