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The inclination of the failure plane behind a vertical wall in the passive pressure case is inclined to the horizontal at
- A${45^o} + \phi$
- B${45^o} - \phi$
- C${45^o} + \frac{\phi }{2}$
- D${45^o} - \frac{\phi }{2}$
Answer not set
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CCommunity
1). 45o+ϕ45o+ϕ