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A light bulb draws 300 mA when the voltage across it is 240 V. The resistance of the light bulb is;
- A400 Ω
- B600 Ω
- C800 Ω
- D1000 Ω
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CCommunity
V = I × R
$(R = \frac{V}{I} = \frac{{240}}{{300 \times {{10}^{ - 3}}}} = 800\;{\rm{\Omega }})$
$(R = \frac{V}{I} = \frac{{240}}{{300 \times {{10}^{ - 3}}}} = 800\;{\rm{\Omega }})$