CCommunity
Let the numbers be x, x+2, x+4 and x+6 then:
Formula:
$(\eqalign{ & Average = {{sum\ of\ elements} \over {number\ of\ elements}} \cr & Required\ average = {{x + x + 2 + x + 4 + x + 6} \over 4} \cr & \Rightarrow 29 = {{4x + 12} \over 4} \cr & \Rightarrow 29 = x + 3 \cr & \Rightarrow x = 26 \cr})$
Hence, the largest numbers = x+6 = 26 + 6 = 32