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An inductor supplied with 100 V AC with a frequency of 10 kHz passes a current of 10 mA. The value of the inductor is
- A1.7 H
- B16 mH
- C1 mH
- D160 mH
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CCommunity
Given that, voltage (V) = 100 V
Frequency (f) = 10 kHz
Current (I) = 10 mA
$({X_L} = \frac{V}{I} = \frac{{100}}{{10 \times {{10}^{ - 3}}}} = {10^4}{\rm{\;\Omega }})$
$(\Rightarrow 2\pi fL = {10^4})$
$(\Rightarrow L = \frac{{{{10}^4}}}{{2\pi \times 10 \times {{10}^3}}} = 159.15\;mH \approx 160\;mH)$
Frequency (f) = 10 kHz
Current (I) = 10 mA
$({X_L} = \frac{V}{I} = \frac{{100}}{{10 \times {{10}^{ - 3}}}} = {10^4}{\rm{\;\Omega }})$
$(\Rightarrow 2\pi fL = {10^4})$
$(\Rightarrow L = \frac{{{{10}^4}}}{{2\pi \times 10 \times {{10}^3}}} = 159.15\;mH \approx 160\;mH)$