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A vessel contains a mixture of P and Q in the ratio of 5 : 3. 16 liters of this mixture is taken out and 5 liters of P is poured in. The ne…

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A vessel contains a mixture of P and Q in the ratio of 5 : 3. 16 liters of this mixture is taken out and 5 liters of P is poured in. The new mixture has ratio of P to Q as 11 : 6. Find the total original quantity of mixture.
  • A80 liters
  • B96 liters
  • C98 liters
  • D84 liters
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P = 5x, Q = 3x

The quantity of P and Q in 16 liters of the mixture.

Quantity of P = (16 × 5x)/8x = 10

Quantity of Q = (16 × 3x)/8x = 6

Now, 5 liters of P poured in and then ratio becomes 11 ? 6

(5x - 10 + 5)/3x - 6 = 11/6

(5x - 5)/(3x - 6) = 11/6

Solve, x = 12

So total mixture originally = 8x = 8 × 12 = 96 liters