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Find the largest number of three digits exactly divisible by 15, 18, 27 and 30?
- A870
- B900
- C810
- D780
Answer not set
Discussion 1
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CCommunity
LCM of 15, 18, 27, 30 = 2 × 3 × 3 × 3 × 5 × 1 × 1 × 1 = 270
After dividing 999 by 270, we get
Remainder = 189
∴ Answer = 999 - 189 = 810
After dividing 999 by 270, we get
Remainder = 189
∴ Answer = 999 - 189 = 810