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A bus travels 2/5 of a total journey at its usual speed. The remaining distance was covered by bus at 6/7 of its usual speed. Due to slow s…

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A bus travels 2/5 of a total journey at its usual speed. The remaining distance was covered by bus at 6/7 of its usual speed. Due to slow speed it reaches its destination 50 minutes late. If the total distance is 200 kms, then what is the usual speed (in km/hr) of bus?

A20.57
B24
C28
D26.52

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Discussion 1

CCommunity25 Jun 2019

Let its usual speed be a km/hr.

From the questions statement 2/5th of total journey is 2 × 200/5 = 80 km

⇒ 80/a + 120/(6a/7) – 200/a = 50/60

⇒ 80 + 140 – 200 = 5a/6

⇒ a = 24

∴ its usual speed is 24 km/hr