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In a chemistry lab two beakers A and B contains 36% and 40% of spirit respectively. If two liters from A is mixed with 4 liters of B. The ratio of sprit and water in the resulting mixture is:
- A19 : 46
- B29 : 46
- C29 : 55
- D29 : 45
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CCommunity
A has 36% spirit.
Amount of spirit in 2 liters of A = 0.36 × 2 = 0.72 liters
B has 40% spirit.
Amount of spirit in 4 liters of B = 0.4 × 4 = 1.6 liters
Total amount of mixture = 2 + 4 = 6 liters
Amount of spirit in the final mixture = 0.72 + 1.6 = 2.32 liters
Amount of water in the final mixture = 6 – 2.32 = 3.68
Required ratio = 2.32 : 3.68 = 29 : 46
Amount of spirit in 2 liters of A = 0.36 × 2 = 0.72 liters
B has 40% spirit.
Amount of spirit in 4 liters of B = 0.4 × 4 = 1.6 liters
Total amount of mixture = 2 + 4 = 6 liters
Amount of spirit in the final mixture = 0.72 + 1.6 = 2.32 liters
Amount of water in the final mixture = 6 – 2.32 = 3.68
Required ratio = 2.32 : 3.68 = 29 : 46