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Two mixtures M1 and M2 contain mixture of two types of pulses P1 and P2. M1 and M2 contain P1 and P2 in the ratio of 4 : 5 and 8 : 3 respec…

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Two mixtures M1 and M2 contain mixture of two types of pulses P1 and P2. M1 and M2 contain P1 and P2 in the ratio of 4 : 5 and 8 : 3 respectively. M1 and M2 are mixed to form a third mixture. Now the ratio of P1 : P2 becomes 8 : 5 in the resultant mixture. Find the amount of pulses P2 in the M2, if the resultant quantity is 364 kg of pulses.

A62 kg
B64 kg
C60 kg
D68 kg

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Discussion 1

CCommunity13 Jul 2019

P2 in M1 = 5/9, in M2 = 3/11 and in resultant mixture = 5/13

By alligation rule : -

5/9 3/11

5/13

(5/13 – 3/11) = 16/143 (5/9 – 3/11) = 20/117

⇒ 16/143 : 20/117 = 36 : 55

∴ Amount of M2 in 364 kg = 55/91 × 364 = 220 kg

Now amount of pulses P2 in M2 = (3/11) × 220 = 60 kg