A bag contains Rs. 1, Rs. 2 and Rs. 5 coins in the ratio of 19 ∶ 5 ∶ 3. When total amount was calculated, it turned out to be Rs. 880. Find…

From given data-

Total amount in the bag = Rs. 880

And Rs. 1, Rs. 2 and Rs. 5 coins are in the ratio of 19 ? 5 ? 3

Let the common multiplication constant be X.

∴ We can say bag contains 19X Rs. 1 coins, 5X Rs. 2 coins and 3X Rs. 5 coins.

∴ Total amount of Rs. 1 coins = 1 × 19X

∴ Total amount of Rs. 1 coins = 19X

∴ Total amount of Rs. 2 coins = 2 × 5X

∴ Total amount of Rs. 2 coins = 10X

∴ Total amount of Rs. 5 coins = 5 × 3X

∴ Total amount of Rs. 5 coins = 15X

As per given data-

Total amount in bag = Total amount of Rs. 1 coins + Total amount of Rs. 2 coins + Total amount of Rs. 5 coins

⇒ 880 = 19X + 10X + 15X

⇒ 880 = 44X

∴ X = 20

∴ Total amount of Rs. 1 coins = 19 × 20

∴ Total amount of Rs. 1 coins = 380 ---- (1)

∴ Total amount of Rs. 2 coins = 10 × 20

∴ Total amount of Rs. 2 coins =200 ---- (2)

∴ Total amount of Rs. 5 coins = 15 × 20

∴ Total amount of Rs. 5 coins = 300 ---- (3)

Therefore, number of 1 rupee coins = 380/1 = 380

Number of 2 rupee coins = 200/2 = 100

Number of 5 rupee coins = 300/5 = 60

∴ Required answer is 380, 100 and 60