3
If (x – 3)2 + (y – 5)2 + (z – 4)2 = 0, then the value of x2/9 + y2/25 + z2/16 is:
- A12
- B9
- C3
- D1
Answer not set
Discussion 1
Log in or create a free account to reply and vote.
0
CCommunity
(x – 3)2 + (y – 5)2 + (z – 4)2 = 0
⇒ (x – 3)2 = 0
⇒ x = 3
⇒ (y – 5)2 = 0
⇒ y = 5
⇒ (z – 4)2 = 0
⇒ z = 4
∴ x2/9 + y2/25 + z2/16 = 9/9 + 25/25 + 16/16 = 3
⇒ (x – 3)2 = 0
⇒ x = 3
⇒ (y – 5)2 = 0
⇒ y = 5
⇒ (z – 4)2 = 0
⇒ z = 4
∴ x2/9 + y2/25 + z2/16 = 9/9 + 25/25 + 16/16 = 3