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In the following question, correct the equation by interchanging two signs.
9 × 3 + 8 ÷ 4 – 7 = 28
9 × 3 + 8 ÷ 4 – 7 = 28
- A× and –
- B+ and –
- C÷ and +
- D× and ÷
Answer not set
Discussion 1
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CCommunity
Given Equation ⇒ 9 × 3 + 8 ÷ 4 – 7 = 28
After interchanging,
1) × and –
⇒ 9 – 3 + 8 ÷ 4 × 7 = 28
⇒ 5 + 2 × 7 = 28
→ 19 = 28 (LHS ≠ RHS) (False)
2) + and –
⇒ 9 × 3 – 8 ÷ 4 + 7 = 28
⇒ 27 – 2 + 7 = 28
→ 33 = 28 (LHS ≠ RHS) (False)
3) ÷ and +
⇒ 9 × 3 ÷ 8 + 4 – 7 = 28
⇒ 3.375 – 3 = 28
→ 0.375 = 28 (LHS ≠ RHS) (False)
4) × and ÷
⇒ 9 ÷ 3 + 8 × 4 – 7 = 28
⇒ 3 + 32 – 7 = 28
⇒ 28 = 28 (True)
After interchanging,
1) × and –
⇒ 9 – 3 + 8 ÷ 4 × 7 = 28
⇒ 5 + 2 × 7 = 28
→ 19 = 28 (LHS ≠ RHS) (False)
2) + and –
⇒ 9 × 3 – 8 ÷ 4 + 7 = 28
⇒ 27 – 2 + 7 = 28
→ 33 = 28 (LHS ≠ RHS) (False)
3) ÷ and +
⇒ 9 × 3 ÷ 8 + 4 – 7 = 28
⇒ 3.375 – 3 = 28
→ 0.375 = 28 (LHS ≠ RHS) (False)
4) × and ÷
⇒ 9 ÷ 3 + 8 × 4 – 7 = 28
⇒ 3 + 32 – 7 = 28
⇒ 28 = 28 (True)