A contractor undertook to do a piece of work in 12 days. He employed certain number of labours, about 3 of them being absent from the very… — Answer & Discussion

A contractor undertook to do a piece of work in 12 days. He employed certain number of labours, about 3 of them being absent from the very first day, the rest could finish the work in 18 days. Find the number of men originally employed?

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Discussion 1

CCommunity09 Jul 2019

Let X be the number of labours employed initially and Y be the work done by each labour in one day

But as 3 of the labours absent and the work was done by the remaining in 18 days

Hence the work done initially by X labours in 12 days will be equal to the work done after the 3 labours are gone.

⇒ 12XY = 18(X - 3) Y

⇒ 12X = 18X - 54

⇒ 6X = 54

∴ X = 9