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What will be the ratio of the surface area of a sphere and the curved surface area of the cylinder circumscribing the sphere?
- A1 ∶ 2
- B1 ∶ 1
- C2 ∶ 1
- D2 ∶ 3
Answer not set
Discussion 1
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CCommunity
We know that,
The surface area of sphere = 4πr2
The curved surface area of cylinder = 2πrh
Diameter of sphere = Height of cylinder
⇒ 2r = h
Ratio $(= \frac{{4{\rm{\pi }}{r^2}}}{{2{\rm{\pi rh\;}}}} = \frac{{4\pi {r^2}}}{{4\pi {r^2}}} = \frac{1}{1})$
The surface area of sphere = 4πr2
The curved surface area of cylinder = 2πrh
Diameter of sphere = Height of cylinder
⇒ 2r = h
Ratio $(= \frac{{4{\rm{\pi }}{r^2}}}{{2{\rm{\pi rh\;}}}} = \frac{{4\pi {r^2}}}{{4\pi {r^2}}} = \frac{1}{1})$