If the unit digit of 433 × 456 × 43N is (N + 2), then what is the value of N?

Check with options:

If N = 1

⇒ 433 × 456 × 431

⇒ Last digit = 8(By multiplying last digits of all 3 number)

Since N + 2 ≠ 8, it will not satisfy the given condition.

If N = 8

⇒ 433 × 456 × 438

⇒ Last digit = 4, it will also not satisfy the given condition.

If N = 3

⇒ 433 × 456 × 433

⇒ Last digit = 4, it will also not satisfy the given condition.

If N = 6

⇒ 433 × 456 × 436

⇒ Last digit = 8 = (N + 2)

∴ N = 6 will satisfy the given condition.