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The least number which should be added to 3475 so that the sum is exactly divisible by 2, 4, 5 and 6, is:
- A6
- B5
- C4
- D7
Answer not set
Discussion 1
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CCommunity
Finding L.C.M of 2, 4, 5 and 6;
Factors of 2 = 2
Factors of 4 = 22
Factors of 5 = 5
Factors of 6 = 2 × 3
L.C.M(2, 4, 5, 6) = 22 × 3 × 5 = 60
Divide 3475 by 60,
⇒ 3475/60 = $(57\frac{{55}}{{60}})$ [Here 55 represent the remainder which need to make 0 for that,60 - 55 need to do. Answer of subtraction is required answer which need to add in 3475]
∴ Number need to add = 60 – 55 = 5
Factors of 2 = 2
Factors of 4 = 22
Factors of 5 = 5
Factors of 6 = 2 × 3
L.C.M(2, 4, 5, 6) = 22 × 3 × 5 = 60
Divide 3475 by 60,
⇒ 3475/60 = $(57\frac{{55}}{{60}})$ [Here 55 represent the remainder which need to make 0 for that,60 - 55 need to do. Answer of subtraction is required answer which need to add in 3475]
∴ Number need to add = 60 – 55 = 5