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If 5@1 = 60; 12@8 = 200; 16@2 = 180; then what is the value of 16@10 = ?
- A32
- B11
- C9
- D260
Answer not set
Discussion 1
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CCommunity
5@1 = (5 + 1) × 10 = 6 × 10 = 60
12@8 = (12 + 8) × 10 = 20 × 10 = 200
16@2 = (16 + 2) × 10 = 18 × 10 = 180
Similarly,
16@10 = (16 + 10) × 10 = 26 × 10 = 260
Hence, answer is 260.
12@8 = (12 + 8) × 10 = 20 × 10 = 200
16@2 = (16 + 2) × 10 = 18 × 10 = 180
Similarly,
16@10 = (16 + 10) × 10 = 26 × 10 = 260
Hence, answer is 260.