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What will be the output of the program ?#include<stdio.h>void main(){ int a[5] = {5, 1, 15, 20, 25}; int i, j, m; i = ++a[1]; j = a[1]++; m = a[i++]; printf("%d, %d, %d", i, j, m);}
- A3, 2, 15
- B2, 3, 20
- C2, 1, 15
- D1, 2, 5
Correct answer: A
Discussion 1
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CCommunity
3, 2, 15
>> int a[5] = {5, 1, 15, 20, 25}; The variable arr is declared as an integer array with a size of 5 and it is initialized to
a[0] = 5, a[1] = 1, a[2] = 15, a[3] = 20, a[4] = 25.
>> int i, j, m; The variable i, j, m are declared as an integer type.
>> i = ++a[1]; becomes i = ++1; Hence i = 2 and a[1] = 2
>> j = a[1]++; becomes j = 2++; Hence j = 2 and a[1] = 3.
>> m = a[i++]; becomes m = a[2]; Hence m = 15 and i is incremented by 1(i++ means 2++ so i=3)
>> printf("%d, %d, %d", i, j, m); It prints the value of the variables i, j, m
Hence the output of the program is 3, 2, 15.
>> int a[5] = {5, 1, 15, 20, 25}; The variable arr is declared as an integer array with a size of 5 and it is initialized to
a[0] = 5, a[1] = 1, a[2] = 15, a[3] = 20, a[4] = 25.
>> int i, j, m; The variable i, j, m are declared as an integer type.
>> i = ++a[1]; becomes i = ++1; Hence i = 2 and a[1] = 2
>> j = a[1]++; becomes j = 2++; Hence j = 2 and a[1] = 3.
>> m = a[i++]; becomes m = a[2]; Hence m = 15 and i is incremented by 1(i++ means 2++ so i=3)
>> printf("%d, %d, %d", i, j, m); It prints the value of the variables i, j, m
Hence the output of the program is 3, 2, 15.