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Determine output:void main(){ int i=0, j=1, k=2, m; m = i++ || j++ || k++; printf("%d %d %d %d", m, i, j, k);}
- A1 1 2 3
- B1 1 2 2
- C0 1 2 2
- D0 1 2 3
- ENone of these
Correct answer: B
Discussion 1
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CCommunity
1 1 2 2
In an expression involving || operator, evaluation takes place from left to right and will be stopped if one of its components evaluates to true(a non zero value).
So in the given expression m = i++ || j++ || k++.
It will be stop at j and assign the current value of j in m.
therefore m = 1 , i = 1, j = 2 and k = 2 (since k++ will not encounter. so its value remain 2)
In an expression involving || operator, evaluation takes place from left to right and will be stopped if one of its components evaluates to true(a non zero value).
So in the given expression m = i++ || j++ || k++.
It will be stop at j and assign the current value of j in m.
therefore m = 1 , i = 1, j = 2 and k = 2 (since k++ will not encounter. so its value remain 2)