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#includevoid main(){ int ptr, a=10; ptr = &a; ptr += 1; printf("%d, %d", *ptr, a);}

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#include<stdio.h>void main(){ int *ptr, a=10; ptr = &a; *ptr += 1; printf("%d, %d", *ptr, a);}

A10, 10
B10, 11
C11, 10
D11, 11

Correct answer: D

Discussion 1

CCommunity11 Jun 2021

11, 11

Address of variable a is assigned to the integer pointer ptr.
Due to the statement;
*ptr += 1;
value at address pointing by ptr incremented by 1.
As the value at address is changed so variable a also get the updated value.

#includevoid main(){ int *ptr, a=10; ptr = &a; *ptr += 1; printf("%d, %d", *ptr, a);}

Discussion 1

#includevoid main(){ int ptr, a=10; ptr = &a; ptr += 1; printf("%d, %d", *ptr, a);}