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Determine Output:void main(){ int i=-1, j=-1, k=0, l=2, m; m = i++ && j++ && k++ || l++; printf("%d %d %d %d %d", i, j, k, l, m);}
- A0 0 1 2 0
- B0 0 1 3 0
- C0 0 1 3 1
- D0 0 0 2 1
Correct answer: C
Discussion 1
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CCommunity
0 0 1 3 1
Logical operations always give a result of 1 or 0 . And also the logical AND (&&) operator has higher priority over the logical OR (||) operator. So the expression 'i++ && j++ && k++' is executed first. The result of this expression is 0 (-1 && -1 && 0 = 0). Now the expression is 0 || 2 which evaluates to 1 (because OR operator always gives 1 except for '0 || 0' combination- for which it gives 0). So the value of m is 1. The values of other variables are also incremented by 1.
Logical operations always give a result of 1 or 0 . And also the logical AND (&&) operator has higher priority over the logical OR (||) operator. So the expression 'i++ && j++ && k++' is executed first. The result of this expression is 0 (-1 && -1 && 0 = 0). Now the expression is 0 || 2 which evaluates to 1 (because OR operator always gives 1 except for '0 || 0' combination- for which it gives 0). So the value of m is 1. The values of other variables are also incremented by 1.