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What is the value of a[1] after the following code is executed?int[] a = {0, 2, 4, 1, 3};for(int i = 0; i < a.length; i++)a[i] = a[(a[i] + 3) % a.length];
- A0
- B1
- C2
- D3
- E4
Correct answer: B
Discussion 1
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CCommunity
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when i = 0;
a[i] = a[(a[i]+3)%a.length] //a.length =5;
a[0] = a[(a[0]+3)%5];
a[0] = a[(0+3)%5] ; // 3
a[0] = a[3] = 1
when i = 1;
a[1]=a[(a[1]+3)%5];
a[1]=a[(2+3)%5];
a[1]=a[0];
a[1]=1;
Therefore a[1] is equal to 1
when i = 0;
a[i] = a[(a[i]+3)%a.length] //a.length =5;
a[0] = a[(a[0]+3)%5];
a[0] = a[(0+3)%5] ; // 3
a[0] = a[3] = 1
when i = 1;
a[1]=a[(a[1]+3)%5];
a[1]=a[(2+3)%5];
a[1]=a[0];
a[1]=1;
Therefore a[1] is equal to 1