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Find the greatest number which leaves the same remainder when it divides 25, 57 and 105.
- A18
- B8
- C12
- D16
Correct answer: D
Discussion 1
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CCommunity
16
105 - 57 = 48
57 - 25 = 32
105 - 25 = 80
The H.C.F of 32, 48 and 80 is 16.
105 - 57 = 48
57 - 25 = 32
105 - 25 = 80
The H.C.F of 32, 48 and 80 is 16.