20
The center of gravity of a trapezium with parallel sides 'a' and 'b' lies at a distance of 'y' from the base 'b', as shown in the below figure. The value of 'y' is
- Ah [(2a + b)/(a + b)]
- B(h/2) [(2a + b)/(a + b)]
- C(h/3) [(2a + b)/(a + b)]
- D(h/3) [(a + b)/(2a + b)]
Correct answer: C