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Sum of present ages of A,B and C is 72 years. If 4 years ago , the ratio of their ages were 1:2:3 respectively, find A’s present age.
- A11 years
- B12 years
- C13 years
- D14 years
Correct answer: D
Discussion 1
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CCommunity
14 years
Sum of present ages of A, B and C is = 72 years
Therefore , Sum of their ages 4 years ago = 72 – (4 * 3)= 60 years.
4 years ago ratio of the ages of A , B and C was = 1:2:3
Therefore, A’s age four years ago = (1/6) * 60 = 10 years.
So , A’s present age =10 + 4 = 14 years
Sum of present ages of A, B and C is = 72 years
Therefore , Sum of their ages 4 years ago = 72 – (4 * 3)= 60 years.
4 years ago ratio of the ages of A , B and C was = 1:2:3
Therefore, A’s age four years ago = (1/6) * 60 = 10 years.
So , A’s present age =10 + 4 = 14 years