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A 200 turn coil having an axial length of 30 mm and a radius of 10 mm is pivoted in a magnetic field having a flux density of 0.8 T. If the coil carries a current of 0.5 A, the torque acting on the coil will be[Hint. Torque = 2BIlNr N-m]
- A8 N-m
- B0.48 N-m
- C0.048 N-m
- D0.0048 N-m
Correct answer: C