18
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
- A50 days
- B60 days
- C70 days
- D80 days
Correct answer: B
Discussion 1
Log in or create a free account to reply and vote.
0
CCommunity
60 days
A + B’s 1 day’s work = 1/30
i.e. A + B = 1/30 --------- (i)
16 A + 44 B = 1 ------ (ii) ( i.e. 1 = the whole work done)
Multiplying (i) by 16 and subtracting it from (ii), we get
i.e. 16 A + 44 B = 1
16 A + 16B = 8/15
28 B =7/15
B = 1/60 i.e. B’s 1 day’s work = 1/60
Therefore, B alone can finish the work in 60 days.
A + B’s 1 day’s work = 1/30
i.e. A + B = 1/30 --------- (i)
16 A + 44 B = 1 ------ (ii) ( i.e. 1 = the whole work done)
Multiplying (i) by 16 and subtracting it from (ii), we get
i.e. 16 A + 44 B = 1
16 A + 16B = 8/15
28 B =7/15
B = 1/60 i.e. B’s 1 day’s work = 1/60
Therefore, B alone can finish the work in 60 days.