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Find the numbers which are in the ratio 3:2:4 such that the sum of the first and the second added to the difference of the third and the second is 21.
- A12, 8, 16
- B6, 4, 8
- C9, 6, 24
- D9, 6, 12
Correct answer: D
Discussion 1
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CCommunity
9, 6, 12
Let the numbers be a, b and c.
a:b:c = 3:2:4
Given, (a + b) + (c - b) = 21
=> a + c = 21
=> 3x + 4x = 21 => x = 3
a, b, c are 3x, 2x, 4x
a, b, c are 9, 6, 12.
Let the numbers be a, b and c.
a:b:c = 3:2:4
Given, (a + b) + (c - b) = 21
=> a + c = 21
=> 3x + 4x = 21 => x = 3
a, b, c are 3x, 2x, 4x
a, b, c are 9, 6, 12.