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Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil's age. After further 8 years, how many times would he be of Sunil's age?
- A15 times
- B8 times
- C11 times
- D2 times
Correct answer: D
Discussion 1
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CCommunity
2 times
Assume that Sunil's present age =x.
Then, father's present age =3x+x=4x
After 88 years, father's age =2 1/2 times of Sunils' age
⇒(4x+8)=2 1/2(x+8)
⇒4x+8=5/2(x+8)
⇒8x+16=5x+40
⇒3x=40−16=24
⇒x=243=8
After further 88 years,
Sunil's age =x+8+8=8+8+8=24
Father's age =4x+8+8=4×8+8+8=48
Father's age/Sunil's age =48/24=2
Assume that Sunil's present age =x.
Then, father's present age =3x+x=4x
After 88 years, father's age =2 1/2 times of Sunils' age
⇒(4x+8)=2 1/2(x+8)
⇒4x+8=5/2(x+8)
⇒8x+16=5x+40
⇒3x=40−16=24
⇒x=243=8
After further 88 years,
Sunil's age =x+8+8=8+8+8=24
Father's age =4x+8+8=4×8+8+8=48
Father's age/Sunil's age =48/24=2