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Raja can do a piece of work in 20 days while Ramesh can finish it in 25 days. Ramesh started working and Raja joined him after 10 days. The whole work is completed in
- A18 days
- B$16\frac{2}{3}$ days
- C20 days
- D15 days
Answer not set
Discussion 1
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CCommunity
$\large 16\frac{2}{3}$ days is correct
Let the total work is $\large 100$ units.
Raja in a day can do $\large 5$ units.
Ramesh in a day can do $\large 4$ units.
Both together can do $\large 9$ units work in a day.
Hence In 1st $\large 10$ days ramesh finished $\large 40$ units of work alone.
$\large 60 $ units of work will be completed by both of them together.
Hence No. of days $\large = \frac{60}{9} + 10 $
$ \large = \frac{50}{3}$
$ \large = 16 \frac{2}{3}$
Let the total work is $\large 100$ units.
Raja in a day can do $\large 5$ units.
Ramesh in a day can do $\large 4$ units.
Both together can do $\large 9$ units work in a day.
Hence In 1st $\large 10$ days ramesh finished $\large 40$ units of work alone.
$\large 60 $ units of work will be completed by both of them together.
Hence No. of days $\large = \frac{60}{9} + 10 $
$ \large = \frac{50}{3}$
$ \large = 16 \frac{2}{3}$