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The denominators of two fractions are 5 and 7 respectively. The sum of these fractions is 41/35 . On interchanging the numerators, their sum becomes 43/35 . The fractions are
- A1/9 and 4/7
- B3/5 and 4/7
- C4/5 and 2/7
- D3/5 and 5/7
Answer not set
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Solution
Let the two fractions be $\frac{x}{5}$ and $\frac{y}{7}$
Acc to ques,
=> $\frac{x}{5} + \frac{y}{7} = \frac{41}{35}$
=> $\frac{7x + 5y}{35} = \frac{41}{35}$
=> $7x + 5y = 41$
After interchanging the numerators
=> $\frac{y}{5} + \frac{x}{7} = \frac{43}{35}$
=> $\frac{5x + 7y}{35} = \frac{43}{35}$
=> $5x + 7y = 43$
Solving above equations, we get :
=> $x = 3 , y = 4$
$\therefore$ Original fractions = $\frac{3}{5} , \frac{4}{7}$
Let the two fractions be $\frac{x}{5}$ and $\frac{y}{7}$
Acc to ques,
=> $\frac{x}{5} + \frac{y}{7} = \frac{41}{35}$
=> $\frac{7x + 5y}{35} = \frac{41}{35}$
=> $7x + 5y = 41$
After interchanging the numerators
=> $\frac{y}{5} + \frac{x}{7} = \frac{43}{35}$
=> $\frac{5x + 7y}{35} = \frac{43}{35}$
=> $5x + 7y = 43$
Solving above equations, we get :
=> $x = 3 , y = 4$
$\therefore$ Original fractions = $\frac{3}{5} , \frac{4}{7}$